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热心网友 时间:2024-11-09 02:14
答案为C1、将i1、i2统一为余弦函数:i1(t)=Imcos(t+π/4)i1(t)=Imsin(t-π/2)=Imcos(t-π/2-π/2)=Imcos(t-π)2、写成相量形式:I1=I∠π/4I2=I∠-π3、相位差为:π/4-π=-3π/4说明i1滞后i2,角度为3π/4